b^2+25=10b

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Solution for b^2+25=10b equation:


Simplifying
b2 + 25 = 10b

Reorder the terms:
25 + b2 = 10b

Solving
25 + b2 = 10b

Solving for variable 'b'.

Reorder the terms:
25 + -10b + b2 = 10b + -10b

Combine like terms: 10b + -10b = 0
25 + -10b + b2 = 0

Factor a trinomial.
(5 + -1b)(5 + -1b) = 0

Subproblem 1

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Subproblem 2

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {5, 5}

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